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Home/ Questions/Q 1697
Gary Christan
Gary Christan
Asked: May 11, 20222022-05-11T13:51:19+00:00 2022-05-11T13:51:19+00:00

How to generically map over values of object in TypeScript (where object keys are a string union)?

Suppose I have two types:

type Credentials = {
  Username: string;
  Password: string;
};

type XmlCredentials = { [k in keyof Credentials]: { _text: string } };

and I want to convert from Credentials to XmlCredentials, wrapping string values of input properties with { _text: _ } object.

I can easily do this manually:

const convertNonGenericManual = (input: Credentials): XmlCredentials => ({
  Username: {
    _text: input.Username,
  },
  Password: {
    _text: input.Password,
  },
});

but this gets cumbersome and repetitive when input types has many properties.

I tried writing the function without repetition:

const convertNonGenericManual = (input: Credentials): XmlCredentials => {
  // TODO this does not type check
  return Object.fromEntries(Object.entries(input).map(([key, value]) => [key, { _text: value }]));
};

And even generically:

const convertGeneric = <T extends readonly string[]>(input: { [k in T[number]]: string }): { [k in T[number]]: { _text: string }; } => {
  // TODO this does not type check
  return Object.fromEntries(Object.entries(input).map(([key, value]) => [key, { _text: value }]));
};

But I was unable to get it to type-check in either case.

Is it possible to achieve this without writing boilerplate code?

Edit:

I think that the problem reduces to being able to iterate over a tuple and having the narrow type in each iteration, which I imagine might not be possible:

const values = ["k1", "k2"] as const;
for (const v of values) {
  // we'd need v to have type "v1" during first iteration and "v2" during second iteration - probably impossible
}

typescript

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